-5x^2+20x=-230

Solution for -5x^2+20x=-230 equation:

-5x^2+20x=-230

We move all terms to the left:

-5x^2+20x-(-230)=0

We add all the numbers together, and all the variables

-5x^2+20x+230=0

a = -5; b = 20; c = +230;
Δ = b2-4ac
Δ = 202-4·(-5)·230
Δ = 5000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5000}=\sqrt{2500*2}=\sqrt{2500}*\sqrt{2}=50\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-50\sqrt{2}}{2*-5}=\frac{-20-50\sqrt{2}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+50\sqrt{2}}{2*-5}=\frac{-20+50\sqrt{2}}{-10}
$